From c07ea13d3077f73ad6cb28e9689b120bca6eac74 Mon Sep 17 00:00:00 2001 From: Jeremy Allison Date: Thu, 8 Jan 2009 10:36:10 -0800 Subject: Fix race condition in alarm lock processing noticed by Richard Sharpe . "It seems to me that if the lock is already held by another process when we enter this code, there is a race between the timeout and the granting. If the lock is subsequently granted, the process releasing the lock will signal the wait variable (or whatever) and our process will be scheduled. However, if the timeout occurs before we are scheduled, the timeout will be delivered first. We will have the lock but will forget we have the lock, and never release it." Jeremy. --- source3/lib/util_tdb.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) (limited to 'source3/lib') diff --git a/source3/lib/util_tdb.c b/source3/lib/util_tdb.c index bb568bc22e..8ceaa46670 100644 --- a/source3/lib/util_tdb.c +++ b/source3/lib/util_tdb.c @@ -64,7 +64,7 @@ static int tdb_chainlock_with_timeout_internal( TDB_CONTEXT *tdb, TDB_DATA key, alarm(0); tdb_setalarm_sigptr(tdb, NULL); CatchSignal(SIGALRM, SIGNAL_CAST SIG_IGN); - if (gotalarm) { + if (gotalarm && (ret == -1)) { DEBUG(0,("tdb_chainlock_with_timeout_internal: alarm (%u) timed out for key %s in tdb %s\n", timeout, key.dptr, tdb_name(tdb))); /* TODO: If we time out waiting for a lock, it might -- cgit